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We (especially me) just have to plan the gas stops.
 

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evildead said:
We (especially me) just have to plan the gas stops.
You have gotten a lot better lately. A LOT better..

- Ice_Hole
 

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20 miles better...
 

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evildead said:
20 miles better...
That is still a 25% increase in mileage :)

- Ice_Hole
 

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Ice_Hole said:
That is still a 25% increase in mileage :)

- Ice_Hole

20% :twofinger
 

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evildead said:
20% :twofinger
Lets give you a math lesson..

20% of 100 is 80.. So you got 20% less MPG then you currently get..

But, if you work the problem the other way. 125% of 80 is 100 mpg. Which is what really happened. So you have 25% better fuel efficiency.

This can be represented by the quation (x+1)(a+d) = a Where x is our percent increase (Or decrease), a is our gas mileage before, d is the difference in mileage before and after. This is the way you represent ammount changed from original, aka 25% more than base ammount.

You represented the problem with the equation (x+1)(c-d) = c Where x is our increase, c is our current gas mileage after the change, and d is the difference between current and past. This way, you represent the ammount you would have to flucuate from current to get the to past ammount. aka 20% less than current ammount.

:blowme :asshole

- Ice_Hole

haha Fun shit..
 

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Thank you. I see now that I was wrong.

I will give you a spelling lesson later, or at least teach you how to spell check.
 

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evildead said:
Thank you. I see now that I was wrong.

I will give you a spelling lesson later, or at least teach you how to spell check.
Well all know I need it..

- Ice_Hole
 

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Ice_Hole said:
Lets give you a math lesson..

20% of 100 is 80.. So you got 20% less MPG then you currently get..

But, if you work the problem the other way. 125% of 80 is 100 mpg. Which is what really happened. So you have 25% better fuel efficiency.

This can be represented by the quation (x+1)(a+d) = a Where x is our percent increase (Or decrease), a is our gas mileage before, d is the difference in mileage before and after. This is the way you represent ammount changed from original, aka 25% more than base ammount.

You represented the problem with the equation (x+1)(c-d) = c Where x is our increase, c is our current gas mileage after the change, and d is the difference between current and past. This way, you represent the ammount you would have to flucuate from current to get the to past ammount. aka 20% less than current ammount.

:blowme :asshole

- Ice_Hole

haha Fun shit..
that's so cool.. but where i come from, 20% of 100 is 20. i've always wanted to learn new math (and 1 + 1 = 3, for very large values of 1)
 

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I've never done well at math. So without using equations we can see that my mistake lay in looking at the ending number (100) and reducing that by 20%. I needed to look at the starting number (80) and increase that by 25% since 20% of 80 is not 20.
 

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evildead said:
I've never done well at math. So without using equations we can see that my mistake lay in looking at the ending number (100) and reducing that by 20%. I needed to look at the starting number (80) and increase that by 25% since 20% of 80 is not 20.
But shouldn't you look at the original (stock) gas mileage?
 

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Clayface said:
But shouldn't you look at the original (stock) gas mileage?
Probably, except I don't remember what it was. I never tested it, always filling up around 100 miles.
 
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