[freakinhungover]

its in another thread but i will be referencing this now..

http://www.motorcycleroads.us

 

[F4Luder]

awesome site .... nice way to plan our next ride ....

 

[freakinhungover]

yeha sxcept theres absolutely nothing in nevada

 

[emanZx6e]

Some of those places makes it hard to find gas going 150 mph.

 

[evildead]

We (especially me) just have to plan the gas stops.

 

[Ice_Hole]

We (especially me) just have to plan the gas stops.

You have gotten a lot better lately. A LOT better..

- Ice_Hole

 

[evildead]

20 miles better...

 

[Ice_Hole]

20 miles better...

That is still a 25% increase in mileage

- Ice_Hole

 

[evildead]

That is still a 25% increase in mileage

- Ice_Hole

20% :twofinger

 

[Ice_Hole]

20% :twofinger

Lets give you a math lesson..

20% of 100 is 80.. So you got 20% less MPG then you currently get..

But, if you work the problem the other way. 125% of 80 is 100 mpg. Which is what really happened. So you have 25% better fuel efficiency.

This can be represented by the quation (x+1)(a+d) = a Where x is our percent increase (Or decrease), a is our gas mileage before, d is the difference in mileage before and after. This is the way you represent ammount changed from original, aka 25% more than base ammount.

You represented the problem with the equation (x+1)(c-d) = c Where x is our increase, c is our current gas mileage after the change, and d is the difference between current and past. This way, you represent the ammount you would have to flucuate from current to get the to past ammount. aka 20% less than current ammount.

:blowme :asshole

- Ice_Hole

haha Fun shit..

 

[evildead]

Thank you. I see now that I was wrong.

I will give you a spelling lesson later, or at least teach you how to spell check.

 

[Ice_Hole]

Thank you. I see now that I was wrong.

I will give you a spelling lesson later, or at least teach you how to spell check.

Well all know I need it..

- Ice_Hole

 

[supermandy]

Lets give you a math lesson..

20% of 100 is 80.. So you got 20% less MPG then you currently get..

But, if you work the problem the other way. 125% of 80 is 100 mpg. Which is what really happened. So you have 25% better fuel efficiency.

This can be represented by the quation (x+1)(a+d) = a Where x is our percent increase (Or decrease), a is our gas mileage before, d is the difference in mileage before and after. This is the way you represent ammount changed from original, aka 25% more than base ammount.

You represented the problem with the equation (x+1)(c-d) = c Where x is our increase, c is our current gas mileage after the change, and d is the difference between current and past. This way, you represent the ammount you would have to flucuate from current to get the to past ammount. aka 20% less than current ammount.

:blowme :asshole

- Ice_Hole

haha Fun shit..

that's so cool.. but where i come from, 20% of 100 is 20. i've always wanted to learn new math (and 1 + 1 = 3, for very large values of 1)

 

[evildead]

I've never done well at math. So without using equations we can see that my mistake lay in looking at the ending number (100) and reducing that by 20%. I needed to look at the starting number (80) and increase that by 25% since 20% of 80 is not 20.

 

[Clayface]

I've never done well at math. So without using equations we can see that my mistake lay in looking at the ending number (100) and reducing that by 20%. I needed to look at the starting number (80) and increase that by 25% since 20% of 80 is not 20.

But shouldn't you look at the original (stock) gas mileage?

 

[evildead]

But shouldn't you look at the original (stock) gas mileage?

Probably, except I don't remember what it was. I never tested it, always filling up around 100 miles.